3y^2-36y+105=0

Solution for 3y^2-36y+105=0 equation:

3y^2-36y+105=0

a = 3; b = -36; c = +105;
Δ = b2-4ac
Δ = -362-4·3·105
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6}{2*3}=\frac{30}{6}
=5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6}{2*3}=\frac{42}{6}
=7
$